Doha, 13 February : Former French Open winner Jelena Ostapenko notun Top-10 win pai loise, Italy laga No. 4 seed Jasmine Paolini ke 6-2, 6-2 haraai, Qatar Open laga women’s singles third-round match te Wednesday din. 27 saal laga Latvian player second set te 2-0 trailing te thakise, hoilebi laga six games lagatar jiti, sirf 63 minutes te match complete korise.
Dusra WTA 1000 event matches te, American sixth-seed Jessica Pegula 10th seed Daria Kasatkina ke 6-3, 7-5 te harai dise, aru fifth-seed Elena Rybakina (Kazakhstan) Rebecca Sramkova ke 7-6(1), 6-2 te haraai advance korise.
Ostapenko, joitu last year Wimbledon quarterfinals reach koribo karone consecutive wins korise, itu hafta te notun consecutive wins aru 12th career Top-5 win paise. Last baar top-10 opponent haraise 2023 Beijing third round te, juntu te Jessica Pegula ke 6-4, 6-2 te harai dise. Next match te, Ostapenko Ons Jabeur nai wild card Sofia Kenin laga against khelibo.
Doha laga current draw te only two Top-5 seeds bacha ase – No. 2 Iga Swiatek aru No. 5 Elena Rybakina, joitu quarterfinal te collision koribo chance ase. Ostapenko laga Doha te strong history ase. 2016 te, 18 saal te, No. 88 rank thakise aru tar prothom WTA Tour final itu jagah te punchise; aru 2022 te semifinals te wapas punchise. 22 Top-10 wins laga char ta Doha laga courts te aahise, juntu 2022 te Garbiñe Muguruza ke 6-2, 6-2 te haraai thaka memorable match include kore.
Paolini against match te Ostapenko laga 22 winners aru 22 unforced errors ase, aru fine serving bhi highlight thakise – nine aces aru first delivery te sirf seven points chhari dise. Paolini sirf nine winners te thakise.
Dusra taraf te, World No. 1 Aryna Sabalenka second round te shocking defeat face korise. Belarusian player Ekaterina Alexandrova (Russia) ke 3-6, 6-3, 7-6 (7/5) te tense two-and-a-half-hour laga match te haraise.
Add Comment